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| CHENMKO ENTERPRISE CO.,LTD SURFACE MOUNT NPN Digital Silicon Transistor VOLTAGE 50 Volts APPLICATION * Switching circuit, Inverter, Interface circuit, Driver circuit. CHDTD113ZKPT CURRENT 500 mAmpere FEATURE * Small surface mounting type. (SC-59/SOT-346) * High current gain. * Suitable for high packing density. * * * * Low colloector-emitter saturation. High saturation current capability. Internal isolated NPN transistors in one package. Built in bias resistor(R1=1.0k, Typ. ) SC-59/SOT-346 (2) (3) 0.95 2.7~3.1 0.95 (1) 1.7~2.1 CONSTRUCTION * One NPN transistors and bias of thin-film resistors in one package. 0.3~0.51 1.2~1.9 0.89~1.3 0.085~0.2 Gnd In 1 0.3~0.6 2.1~2.95 0~0.1 CIRCUIT 2 R2 TR R1 3 Out Dimensions in millimeters SC-59/SOT-346 LIMITING VALUES In accordance with the Absolute Maximum Rating System (IEC 60134). SYMBOL VCC VIN IC PTOT TSTG TJ RJ-S Note 1. Transistor mounted on an FR4 printed-circuit board. 2004-01 PARAMETER Supply voltage Input voltage DC Output current Total power dissipation Storage temperature Junction temperature Thermal resistance CONDITIONS - -5 - Tamb 25 OC, Note 1 - MIN. MAX. 50 +10 500 200 +150 150 150 V V UNIT mA mW O -55 - junction - soldering point - C C C/W O O RATING CHARACTERISTIC ( CHDTD113ZKPT ) CHARACTERISTICS Tamb = 25 C unless otherwise specied. SYMBOL VIoff) VI(on) VO(on) II IO(off) hFE R1 R2/R1 fT PARAMETER Input off voltage Input on voltage Output voltage Input current Output current DC current gain Input resistor Resistor ratio Transition frequency IE=-5mA, VCE=10.0V f=100MHz = CONDITIONS IO=100uA; VCC=5.0V IO=20mA; VO=0.3V IO=50mA; II=2.5mA VI=5V VI=0V; VCC=50V IO=50mA; VO=5.0V - - - - 56 0.7 8.0 - MIN. 0.3 - - 0.1 - - - 1.0 10.0 200 TYP. - 3.0 0.3 7.2 0.5 - 1.3 12.0 - K MHz MAX. V V V mA uA UNIT Note 1.Pulse test: tp300uS; 0.02. RATING CHARACTERISTIC CURVES ( CHDTD113ZKPT ) Typical Electrical Characteristics Fig.1 Input voltage vs. output current (ON characteristics) 100 50 VO= 0.3V Fig.2 Output current vs. input voltage (OFF characteristics) 10m 5m OUTPUT CURRENT : Io (A) VCC= 5V INPUT VOLTAGE : VI(on) (V) 2m 1m 20 10 5 2 1 500m 200m 100m 500u 1m 10m 100m 500m Ta =- 40OC 25OC = 100OC Ta=100OC 25OC -40 OC 100u 10u 1u 0 1.0 2.0 3.0 INPUT VOLTAGE : VI(off) (V) OUTPUT CURRENT : IO (A) Fig.3 DC current gain vs. output current 1k 500 DC CURRENT GAIN : GI Fig.4 Output voltage vs. output current 1 lO/lI=20 500m OUTPUT VOLTAGE : VO(on) (V) VO = 5V Ta=100OC 25OC -40OC 200 100 50 20 10 5 2 1 500u 1m 200m 100m 50m 20m 10m 5m 2m Ta=100OC 25OC -40 OC 10m 100m 500m 1m 500u 1m 10m 100m 500m OUTPUT CURRENT : IO (A) OUTPUT CURRENT : IO (A) |
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